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Average oxidation number is fractional for atleast one of the element in all these compounds except

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${Pb}_{3} O_{4}$

${Mn}_{2} O_{3}$

$N_{3} H$

${KO}_{2}$

answer is C.

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Detailed Solution

$(1) \overset{+ 8 / 3}{{Pb}_{3}} \overset{- 2}{O_{4}}$

$(2) \overset{+ 1}{K} \overset{- 1 / 2}{O_{2}}$

$(3) \overset{+ 3}{{Mn}_{2}} \overset{- 2}{O_{3}}$

$(4) \overset{+ \frac{1}{3}}{N_{3}} \overset{- 1}{H_{}}$

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