Average velocity of a particle in projectile motion between its starting point and the highest point of its trajectory is (projection speed = u, angle of projection from horizontal = $θ$ )

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$\frac{u}{2} \sqrt{1 + \cos^{2} θ}$

$\frac{u}{2} \sqrt{2 + \cos^{2} θ}$

$u \cos θ$

$\frac{u}{2} \sqrt{1 + 3 \cos^{2} θ}$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$s = \sqrt{H^{2} + R^{2} / 4}$

$H = \frac{u^{2} \sin^{2} θ}{2 g}, R = \frac{u^{2} \sin 2 θ}{g}$

Average velocity $= \frac{S}{t} = \frac{S}{T / 2} = \frac{25}{T} = \frac{2 (\sqrt{H^{2} + {(\frac{R}{2})}^{2}})}{T}$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE