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B, P, A and Q are the elements belonging to 17^th group of Modern periodic table. The correct trend of atomic radiusin these elements is B < P < A < Q. The element ‘A’ in the sequence is

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answer is B.

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Detailed Solution

Atomic radius….F<Cl<Br<I;

Density ….F<Cl<Br<I;

IP ….F>Cl>Br>I;

EN ….F>Cl>Br>I;

Electron gain enthalpy ….I<Br<F<Cl; Due to small size and inter electronic repulsions in Fluorine ;

IP …..I^-<Br^-<F^-<Cl^-;

IP trend….F>Cl>Br>I>Cl^->F^->Br^->I^-

B.D.E….Cl₂>Br₂>F₂>I₂; Due to small size and repulsions between lone pairs on adjacent Fluorine atoms ;

IP …..I^-<Br^-<F^-<Cl^-;

Reactivity and oxidizing power…..F₂>Cl₂>Br₂>I₂;

Hydration enthalpy…F^->Cl^->Br^->I^-;

MP and BP ….F₂<Cl₂<Br₂<I₂; Due to increased strength of London dispersion forces;

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