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Q.

B1, B2 and B3 are three identical bulbs connected as shown in the figure. when all three bulbs glow, a current of 3A is recorded by the ammeter. What will happens to the reading of A1, A2, A3 and A when the bulb B2 gets fused?[283][284]


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a

Current reading in A1 will be non zero

b

Current reading in will be less than A1

c

Current reading in A1 will be non zero and current reading in A1 and A3 will be the same[285][286]

d

All of the above 

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Detailed Solution

B1, B2 and B3 are three identical bulbs connected as shown in figure. when all three bulbs glow, a current of 3A is recorded by the ammeter. When the bulb B2 gets fused[289][290] current reading in A2 will be zero and current reading in A1 and A3 will be the same[291][292].
When all three lamps are lit, the parallel combination will be resistant.
1/Rp=1/R+1/R+1/R
 3/R[293][294]
 Rp=R/3
Ammeter A reads 3A current So,
V=IRp
4.5=3R/3
R=4.5 ohm
So, the resistance of each bulb = 4.5 ohm
Now when the bulb B2, gets fused, the equivalent resistance of parallel combination of B1 and B3 is[295][296]
1/Rp=1/R+1/R
1/Rp=2/R
Rp=R/2
Ammeter A reads now,
I'=V/RP
=4.5/(R/2)
I'=2A
Since the resistance of each arm is the same and potential difference is also the same, current divides them equally. So, 1 A[297][298] current will pass through each bulb B1 and B3.[299][300][301][302]
Therefore, the ammeter A1 and A3 reads 1 A current while A2 [303][304]will read zero and A read 2 A currents.
 
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