${\mathrm{BaCO}}_3\left(\mathrm{s}\right)+\mathrm{AcOH}\frac{{\mathrm{Na}}_2{\mathrm{C}}_2{\mathrm{O}}_4\text{ solution }}{\mathrm{\Delta }}\to ?$

Comment on the product of this reaction:

${\mathrm{Ba}}^{2+}+{\mathrm{C}}_2{\mathrm{O}}_4^{2-}⟶{\mathrm{BaC}}_2{\mathrm{O}}_4\downarrow (\mathrm{white} \mathrm{ppt}.)$

                $\text{ (Soluble in }\mathrm{AcOH}\text{ and }{\mathrm{H}}_2{\mathrm{C}}_2{\mathrm{O}}_4\text{ ) }$

Note : ${\mathrm{CaC}}_2{\mathrm{O}}_4$is insoluble in $\text{ dil. }\mathrm{AcOH},{\mathrm{H}}_2{\mathrm{C}}_2{\mathrm{O}}_4$  and ${\left({\mathrm{NH}}_4\right)}_2{\mathrm{C}}_2{\mathrm{O}}_4$ solution, but soluble in $\text{ dil. }\mathrm{HCl}$ and $\text{ dil. }{\mathrm{HNO}}_3\text{. }$