Bacteriophage lambda has 48502 base pairs (bp). Calculate the length of DNA in this virus.

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4.49 x 10^-6 m

10.49 x 10^-6 m

16.49 x 10^-6 m

6.49 x 10^-6 m

answer is D.

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Detailed Solution

Take the distance between two consecutive base pairs as 0.34 nm (0.34×10^–9 m). If the bacteriophage lambda has 48502 base pairs (bp), the length of the DNA double helix is calculated by simply multiplying the total number of base pairs with the distance between two consecutive base pairs. That is, 48502 bp × 0.34 × 10^-9m. It comes out to be approximately 16.49 x 10^-6 m approximately.

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