Q.

Bag I contains 3 red and 4 black balls. Bag II contains 5 red and 6 black balls. If one ball is drawn at random from one of the bags and it is found to be red , then the probability that it was drawn from bag II is  

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a

3768

b

3168

c

4168

d

3568

answer is B.

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Detailed Solution

Question Image

P(B1)=P(B2)=12
Now,P(RB1)=37,P(RB2)=511
Required probability
P(B2R)=P(B2)P(RB2)P(B1)P(RB1)+P(B2)P(RB2) =12(511)12(37+)12(511) =3568

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