Q.

Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

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Detailed Solution

Let the age of Baichung be x years.

Age of Baichung’s father = x + 29

Age of Baichung’s grandfather = Age of Baichung's father + 26 = x + 29 + 26 = x + 55

The Sum of the ages of all three is 135 years (Given)

Baichung's age + Baichung's father's age + Baichung's grandfather's age = 135

⇒ x + (x + 29) + (x + 55) = 135

⇒ 3x + 84 = 135

⇒ 3x = 135 - 84

⇒ 3x = 51

⇒ x = 51/3

⇒ x = 17

Thus, we get the ages of each of them as

Age of Baichung = 17 years

Age of Baichung’s father = x + 29 = 17 + 29 = 46 years

Age of Baichung’s grandfather = x + 55 = 17 + 55 = 72 years

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Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?