Balance the equation: $$HNO3+Ca(OH)2$$→$$Ca(NO3)2+H2O$$

2 HNO 3 + Ca ( OH ) 2 → Ca ( NO 3 ) 2 + 2 H 2 O

Balance the equation: $$HNO3+Ca(OH)2$$→$$Ca(NO3)2+H2O$$

2 HNO 3 + Ca ( OH ) 2 → Ca ( NO 3 ) 2 + 2 H 2 O

4 HNO 3 + Ca ( OH ) 2 → Ca ( NO 3 ) 2 + 2 H 2 O

2 HNO 3 + Ca ( OH ) 2 → Ca ( NO 3 ) 2 + 2 H 2 O

2 HNO 3 + Ca 2 ( OH ) 2 → Ca ( NO 3 ) 2 + 2 H 2 O

2 HNO 3 + Ca ( OH ) 2 → Ca ( NO 3 ) 2 + 4 H 2 O

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Balance the equation: ${HNO}_{3} + Ca {(OH)}_{2} \to Ca {({NO}_{3})}_{2} + H_{2} O$

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4 {HNO}_{3} + Ca {(OH)}_{2} \to Ca {({NO}_{3})}_{2} + 2 H_{2} O

2 {HNO}_{3} + Ca {(OH)}_{2} \to Ca {({NO}_{3})}_{2} + 2 H_{2} O

2 {HNO}_{3} + {Ca}_{2} {(OH)}_{2} \to Ca {({NO}_{3})}_{2} + 2 H_{2} O

2 {HNO}_{3} + Ca {(OH)}_{2} \to Ca {({NO}_{3})}_{2} + 4 H_{2} O

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detailed solution

Correct option is B

A chemical reaction must have an equal quantity of each element on the reactant side and product side in order for it to be balanced. A chemical equation must be balanced in order to guarantee the application of the law of conservation of matter.The number of components on the left-hand side (lhs) must match the number of elements on the right-hand side in order for a particular response to be balanced (rhs).
Think about the following chemical equation:

${HNO}_{3} + Ca (OH)_{2} \to Ca {({NO}_{3})}_{2} + H_{2} O$

Consider the number of moles of each element on both reactant and product side:
On the LHS (no of moles of each element):
H−3
N−1
Ca−1
O−5
On the RHS (no of moles of each element):
H−2
N−2
Ca−1
O−7We must balance it since the number of oxygen, hydrogen, and nitrogen moles on the LHS and RHS are not equal.
Let's first create the HNO₃-2 coefficient by balancing the number of nitrogen moles. The equation will then be:

$2 {HNO}_{3} + Ca (OH)_{2} \to Ca {({NO}_{3})}_{2} + H_{2} O$

On the LHS (no of moles of each element):
H−4
N−2
Ca−1
O−8
On the RHS (no of moles of each element):
H−2
N−2
Ca−1
O−7
Now let’s balance the number of moles of H on the LHS and RHS.Make the H₂O−2 coefficient to bring their numbers into balance. The equation will then be:

$2 {HNO}_{3} + Ca (OH)_{2} \to Ca {({NO}_{3})}_{2} + 2 H_{2} O$

On the LHS (no of moles of each element):On the LHS (no of moles of each element):
H−4
N−2
Ca−1
O−8
On the RHS (no of moles of each element):
H−4
N−2
Ca−1
O−8
Now the number of moles of each element on both sides has been equal and we got the balance chemical equation as:

$2 {HNO}_{3} + Ca (OH)_{2} \to Ca {({NO}_{3})}_{2} + 2 H_{2} O$