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Q.

Balance the reaction MnO4+SO32Mn+2+SO42 in acid medium
(or)
Write the balanced equation for the oxidation of sulphite ions to sulphate ions in acid medium by permanganate ion.

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Detailed Solution

Equation
Question Image
Oxidation half reaction SO32SO42
1) Balance the atoms other than H and O
SO32SO42
2) Balance of oxygen atoms
SO32+H2OSO42
3) Balance of Hydrogen atoms
SO32+H2OSO42+2H+
4) Balance of charges
SO32+H2OSO42+2H++2e(1)
Reduction half reaction MnO4Mn2+
1) Balance the atoms other than H and O
MnO4Mn2+
2) Balance of oxygen atoms
MnO4Mn2++4H2O
3) Balance of Hydrogen atoms
MnO4+8H+Mn2++4H2O
4) Balance of charges
MnO4+8H++5eMn2++4H2O ----(2)
Balancing of electrons in both sides
Adding the two half reaction
1×5; 5SO32+5H2O 5SO42+10H++10e----(3)
2×2;2MnO4+16H++10e2Mn2++8H2O ----(4)
(3) + (4)
2MnO4+5SO32+16H++5H2O2Mn2++5SO42+10H++8H2O
2MnO4+5SO32+6H+2Mn2++5SO42+3H2O

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Balance the reaction MnO4−+SO3−2→Mn+2+SO4−2 in acid medium(or)Write the balanced equation for the oxidation of sulphite ions to sulphate ions in acid medium by permanganate ion.