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Ball 1 collides with an another identical ball 2 at rest as shown in figure. For what value of coefficient of restitution e, the velocity of second ball become two times that of 1 after collision?

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answer is 0.33.

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Detailed Solution

After collision $v_{2} = (\frac{1 + e}{2}) u$

and $v_{2} = (\frac{1 - e}{2}) u$

Here, $u =$ initial speed of ball 1

$v_{} = 2 v_{1}$ when $e = \frac{1}{3}$

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