Ball A of mass m after sliding from an inclined plane strikes elastically with another ball B of mass 3m at rest. The minimum height h, so that the ball B just completes the circular portion of the surface at C, will be nR then value of n (all surfaces are smooth)

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 10.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$\begin{matrix} u_{A} = \sqrt{2 gh}, v_{B} = \frac{2 m_{1} u_{A}}{m_{1} + m_{2}} = \frac{u_{A}}{2} = \frac{\sqrt{2 gh}}{2} \\ To complete vertical circle, v_{B}^{2} = 5 gR \Rightarrow \\ \frac{2 gh}{4} = 5 gR ∴ h = 10 R \end{matrix}$

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE