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Barium is readily attacked by air to form

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$Ba (OH)_{2}, {Ba}_{3} N_{2}$

${Ba}_{3} N_{2}, {BaCO}_{3}$

$BaO, {Ba}_{3} N_{2}$

$BaO, {BaCO}_{3}$

answer is C.

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Detailed Solution

→Ba is highly reactive metal it can readily reacts with atmospheric air [O₂ & N₂] and forms respective oxide & nitride

$2 Ba + O_{2} (air) \to 2 BaO$

$3 Ba + N_{2} (air) \to {Ba}_{3} N_{2}$

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