Questions  

Based on acetic acid Ka=1.8×105 solution,

If the solution obtained in Q.99 is diluted 10 times, it pH becomes

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a
4.75
b
3.75
c
5.75
d
6.25
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detailed solution

Correct option is A

MCH3COONa=82gmol1nCII3COONam/M0.82g/82gmol10.01molcCH3COONa=n/V=0.01mol/0.1L=0.1MpH=pKa+log[salt]/[ acid ]=log1.8×105+log(0.1/0.1)=4.75

from the given condition the solution is diluted 10 times. then 

The pH of buffer solution does not change on dilution.

 


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