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Q.

Based on acetic acid Ka∘=1.8×10−5 solution, 

The degree of dissociation of 0.05 M acetic acid solution is

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a

0.45

b

0.0019

c

0.19

d

0.019

answer is B.

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Detailed Solution

CH3COOH⇌CH3COO−+H+c(1−α)cα cα 

Ka=CH3COO−H+CH3COOH=(cα)(cα)c(1−α)≃cα2

α=Ka/c=1.8×10−5/0.05=0.019

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