Based on the data given below, the correct order of reducing power is : 
$\begin{array}{l}{{\mathrm{Fe}}^{3+}}_{\left(\mathrm{aq}\right)}+\mathrm{e}⟶{{\mathrm{Fe}}^{2+}}_{\left(\mathrm{aq}\right)};{\mathrm{E}}^{\circ }=0.77\mathrm{V}\\ {{\mathrm{Al}}^{3+}}_{\left(\mathrm{aq}\right)}+3\mathrm{e}⟶{\mathrm{Al}}_{\left(\mathrm{s}\right)};{\mathrm{E}}^{\circ }=-1.66\mathrm{V}\\ {\mathrm{Br}}_{2\left(\mathrm{aq}\right)}+2{\mathrm{e}}^{-}⟶2{{\mathrm{Br}}^{-}}_{\left(\mathrm{aq}\right)};{\mathrm{E}}^{\circ }=+1.08\mathrm{V}\end{array}$

The electrode with lower the standard reducing potential $\left(E_{SRP}^o\right)$will have strong tendency to  oxidize itself and have strog reducing power. 

The order of SRP  $Al>\hspace{0.17em}\hspace{0.17em}F{e}^{2+\hspace{0.17em}}>\hspace{0.17em}B{r}^{-}$

Order of reducing power : $Al>\hspace{0.17em}F{e}^{2+}>B{r}^{-}$