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Q.

Based on the equilibrium constant for the reaction below :
$2 {SO}_{3} (g) ⇌ 2 {SO}_{2} (g) + O_{2} (g) K = 1.8 \times 10^{- 5}$
What is the equilibrium constant for the reaction
${SO}_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ {SO}_{3} (g) K = ?$

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a

$4.2 \times 10^{- 3}$

b

$2.1 \times 10^{- 3}$

c

$2.4 \times 10^{2}$

d

$5.6 \times 10^{4}$

answer is C.

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Detailed Solution

The equilibrium constant for the second reaction can be calculated as,

$K^{'} = \frac{1}{\sqrt{K}} K^{'} = \frac{1}{\sqrt{1.8 \times 10^{- 5}}} K' = 2.4 \times 10^{2}$

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Based on the equilibrium constant for the reaction below :2SO3(g)⇌2SO2(g)+O2(g) K=1.8×10−5What is the equilibrium constant for the reaction SO2(g)+12O2(g)⇌SO3(g) K=?