Based on the reaction given below, what is the correct decreasing order of reactivity of metals ?

$\mathrm{i}){\mathrm{Zn}}_{\left(\mathrm{s}\right)}+{\mathrm{CuSO}}_{4\left(\mathrm{aq}\right)}\to {\mathrm{ZnSO}}_{4\left(\mathrm{aq}\right)}+{\mathrm{Cu}}_{\left(\mathrm{s}\right)}$

$\mathrm{ii}){\mathrm{Fe}}_{\left(\mathrm{s}\right)}+{\mathrm{CuSO}}_{4\left(\mathrm{aq}\right)}\to {\mathrm{FeSO}}_{4\left(\mathrm{aq}\right)}+{\mathrm{Cu}}_{\left(\mathrm{s}\right)}$

$\mathrm{iii}){\mathrm{Cu}}_{\left(\mathrm{s}\right)}+2{\mathrm{AgNO}}_{3\left(\mathrm{aq}\right)}\to \mathrm{Cu}{\left({\mathrm{NO}}_3\right)}_{2\left(\mathrm{aq}\right)}+2{\mathrm{Ag}}_{\left(\mathrm{s}\right)}$

$\mathrm{iv}){\mathrm{Zn}}_{\left(\mathrm{s}\right)}+{\mathrm{FeSO}}_{4\left(\mathrm{aq}\right)}\to {\mathrm{ZnSO}}_{4\left(\mathrm{aq}\right)}+{\mathrm{Fe}}_{\left(\mathrm{s}\right)}$

i) From equation (i), we known that Zn is highly reactive than Cu

ii) From equation (ii), we known that Fe is highly reactive than Cu

iii) From equation (iii), we known that Cu is highly reactive than Ag

So, from equations i, ii, iii and iv decreasing  order  of  reactivity  of metals is $\mathrm{Zn}>\mathrm{Fe}>\mathrm{Cu}>\mathrm{Ag}$.