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Q.

(b×c)·(a×d)+(c×a)·(b×d)+(a×b)·(c×d)=

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a

2

b

1

c

–1

d

0

answer is A.

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Detailed Solution

=(b×c)·(a×d)+(c×a)·(b×d)+(a×b)·(c×d)

=b·ab·dc·ac·d+c·bc·da·ba·d+a·ca·db·cb·d

=  (a·b) (c·d)-(a·c) (b·d)+(b·c) (a·d)  -(a·b) (c·d)+(a·c) (b·d)-(b·c) (a·d)

 =0

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(b×c)·(a×d)+(c×a)·(b×d)+(a×b)·(c×d)=