$[b c b \times c] + {\{b \cdot c\}}^{2} =$

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$| b | + | c |$

${(b + c)}^{2}$

$| b |^{2} | c |^{2}$

$| b |^{2} + | c |^{2}$

answer is D.

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Detailed Solution

$\begin{array}{rcl} (b \times c) \cdot (b \times c) + {(b \cdot c)}^{2} & = & | b \times c |^{2} + {(b \cdot c)}^{2} = | b |^{2} | c |^{2} \end{array}$

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