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Q.

Beats are produced by two waves
$y_{1} = a \sin 1000 πt, y_{2} = a \sin 998 πt$
The number of beats heard/sec is

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a

2

b

1

c

0

d

4

answer is C.

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Detailed Solution

$n_{1} = \frac{1000 π}{2 π} = 500 Hz and n_{2} = \frac{998 π}{2 π} = 499 Hz$
Hence beat frequency = $n_{1} - n_{2} = 1$

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