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Benzene and toluene form nearly ideal solutions. At 20 °C, the vapour pressure of benzene is 75 Torr and that of toluene is 22 Torr. The partial vapour pressure of benzene at 20 °C for a solution containing 78 g of benzene and 46 g toluene in Torr is

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37.5

53.5

answer is C.

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Detailed Solution

Amount of benzene, $n_{1} = \frac{m_{1}}{M_{1}} = \frac{78 g}{78 g {mol}^{- 1}} = 1 mol$

Amount of toluene, $n_{2} = \frac{m_{2}}{M_{2}} = \frac{46 g}{92 g {mol}^{- 1}} = 0.5 mol$

Amount fraction of benzene, $x_{1} = \frac{n_{1}}{n_{1} + n_{2}} = \frac{1}{1.5}$

Partial pressure of benzene, $p_{1} = x_{1} p_{1}^{*} = (\frac{1}{1.5}) (75 Torr) = 50 Torr$

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