Benzene burns according to the following equation :
$2 C_{6} H_{6} (l) + 15 O_{2} (g) ⟶ 12 {CO}_{2} (g) + 6 H_{2} O (l)$ $Δ H^{\circ} = - 6542 kJ / mol$
What is the $Δ E^{\circ}$ for the combustion of 1.5 mol of benzene?

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$- 3271 kJ$

$- 9813 k J$

$- 4906 k J$

None of these

answer is D.

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Detailed Solution

$Δ E^{\circ} = [- 6542 + 3 \times \frac{8.314 \times T}{1000}] \times \frac{1.5}{2}$

Temperature is not mentioned.

Since none of the given options included temperature in it, option D is correct.

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