Benzene carbaldehyde is reacted with concentrated NaOH solution to give the products A and B. The product A can be used food preservative and the product B is an aromatic hydroxy compound where OH group is linked to $S{P}^3$ hybridised carbon atom next to Benzene ring. The products A and B are respectively.

 

Benzene Carbaldehyde is treated with concentrated NaOH solution to give salt of carboxylic acid (Sodium Benzoate) and another compound formed is Alcohol (phenyl methanol). This reaction is Cannizaro’s reaction.

Sodium benzoate is used as food preservatives and Phenyl methanol is aromatic hydroxy compound where  OH group is linked to carbon which is saturated carbon ($S{P}^3$) 

Therefore, the correct answer is option (B) Sodium benzoate and phenyl methanol