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Q.

${BF}_{3} + NaH \overset{450 K}{\to} X + NaF X + LiH \to Y$
in these reactions X and Y are

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a

$X = {BH}_{3} . CO Y = {LiAlH}_{4}$

b

$X = B_{2} H_{6} Y = {LiBH}_{4}$

c

$X = {BH}_{3} CO Y = {LiBH}_{4}$

d

$X = B_{2} H_{6} Y = B_{3} N_{3} H_{6}$

answer is B.

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Detailed Solution

$2 {BF}_{3} + 6 NaH \overset{450 k}{\to} B_{2} H_{6} + 6 NaF 2 LiH + B_{2} H_{6} \to 2 {LiBH}_{4}$

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