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Q.

Binding energy per nucleon Vs mass number curve for nuclei is shown in the figure. W, X, Y and Z are four nuclei indicated on the curve. The process that would release energy is

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a

$y \to 2Z\$

b

$W \to X + Z\$

c

$W \to 2Y\$

d

$X \to Y + Z$

answer is C.

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Detailed Solution

$If{\text{ }}it{\text{ }}was{\text{ }}A,y \to 2z$

$Reactant{\text{ }}:{\text{ }}R{\text{ }}= 60 \times 8.5 = 510MeV$

$Product{\text{ }}:{\text{ }}P{\text{ }} = 2 \times 30 \times 5 = 300MeV$

$\Delta E = - 210MeV,Endothermic.$

$If{\text{ }}it{\text{ }}was{\text{ }}B{\text{ }},w \to x + z$

$R = 120 \times 7.5 = 900MeV$

$P = 90 \times 8 + 30 \times 5 = 300MeV$

$\Delta E = - 30MeV, endothermic$

$If{\text{ }}it{\text{ }}was{\text{ }}C,w \to 2y$

$R = 120 \times 7.5 = 900MeV$

$P = 2 \times 60 \times 8.5 = 1020MeV$

$\Delta E = 120MeV,Exothermic.$

$If{\text{ }}it{\text{ }}was{\text{ }}D,x \to y + z\$

$R = 90 \times 8.0 = 720MeV$

$P = 60 \times 8.5 + 30 \times 5 = 660MeV$

$\Delta E = - 60MeV,Endothermic.$

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