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Block is in equilibrium and the tension in the string AB is 300 N. Then choose the correct option(s). (Take g = 10 $m / s^{2}$ , $\tan 37^{0} = \frac{3}{4}$ and neglect the mass of the rod CD)

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Force of compression in the rod CD is 480 N

Mass of the block is 50 kg

The tension in the string CE is 300 N

The ratio of force $F_{2} a n d F_{1}, (|\frac{F_{2}}{F_{1}}|) i s \frac{5}{3}$

answer is A, B, C, D.

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Detailed Solution

$T_{2} = T_{1} \sin 37^{0} ...... (i) F_{1} = T_{1} \cos 37^{0} ...... (i i) F_{2} = T_{1} \cos 37^{0} / \cos 53^{0} ...... (i i i) M g = T_{1} \sin 37^{0} + F_{2} \sin 53^{0} ...... (i v)$

From the above equation find $F_{1}, F_{2}, T_{2}$ and mass of the

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