Body A of mass 4m moving with speed u collides with another body B of mass 2m, at rest. The collision is head on and elastic in nature. After the collision the fraction of energy lost of the colliding body A is :

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4/9

1/9

8/9

5/9

answer is D.

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Detailed Solution

Fractional loss of KE of the colliding body A:
$\frac{∆ KE}{KE} = \frac{4 (m_{1} m_{2})}{{(m_{1} + m_{2})}^{2}} = \frac{4 (4 m) 2 m}{{(4 m + 2 m)}^{2}} = \frac{32 m^{2}}{36 m^{2}} = \frac{8}{9}$

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