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$B (OH)_{3} + NaOH ⇌ {NaBO}_{2} + Na [B (OH)_{4}] + H_{2} O$
How can this reaction be made to proceed in forward direction?

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Addition of borax

Addition of c is 1,2-diol

Addition of ${Na}_{2} {HPO}_{4}$

Addition of trans 1, 2-diol

answer is A.

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Detailed Solution

$B (OH)_{3} + NaOH ⇌ {NaBO}_{2} + Na {[B (OH)_{4}]}^{-} + H_{2} O$

The addition of cis-1,2-diols to the reaction flask causes them to consume ${[B (OH)_{4}]}^{-}$ , which proceed the reaction in the forward direction.

Correct option is A.

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