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Q.

Boiling CuCl₂ with Cu in concentrated HCl produces

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a

${Cu}_{2} O (s)$

b

${CuCl}_{3}^{-}$

c

${CuCl}_{4}^{2 -}$

d

$CuCl (s)$

answer is A.

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Detailed Solution

The reaction is

${CuCl}_{2} + 2 HCl + Cu \to 2 H [{CuCl}_{2}]$

Hydrogen dichloridocuprate is created when copper chloride reacts with hydrogen chloride and copper (I).

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