Boiling point of a solution containing 1.28gram of naphthalene in 100gram $C C l_{4}$ is 350.5K. An unknown compound of mass 2.16grams in 200gram $C C l_{4}$ yields a solution with boiling point of 350.6K. If the molar mass of unknown compound is $x g m o l^{- 1}$ , then the value of $\frac{x}{10}$ is (Boiling point of $C C l_{4}$ is 350 K)

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answer is 9.

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Detailed Solution

$0.5 = K_{b} \times \frac{1.28}{128} \times \frac{1000}{100} K_{b} = 5 k g K m o l^{- 1} 0.6 = 5 \times \frac{2.16}{M} \times \frac{1000}{200} M = 90$

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