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Boltzmann constant represents the gas constant per

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one mole

an Avogadro number of molecules

any number of molecules

one molecule

answer is D.

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Detailed Solution

The average kinetic energy of a gas molecule $E_{K} = \frac{3}{2} \frac{RT}{N} = \frac{3}{2} K . T . where K = \frac{R}{N} = Boltzmann constant$

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