Bond angle (H-O-H) in H₂O is

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90°

104°30'

107°18'

109°28'

answer is B.

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Detailed Solution

In H₂O, central atom 'O' consists of two lone pairs and two bond pairs and It undergoes sp³ hybridization, So there exists lp-lp repulsion which is more than lp-bp repulsion than bp-bp repulsion. Thus, the angle is reduced to 104.5° from 109.5°.

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