Bond angle in H₂O according to VBT  is

• If we apply VBT to explain the shape of water molecule,

$\mathrm{O}-2{\mathrm{s}}^{2}2{\mathrm{p}}_{\mathrm{x}}^{2}2{\mathrm{p}}_{\mathrm{y}}^{1}2{\mathrm{p}}_{\mathrm{z}}^1 ;$

$\mathrm{H}-1{\mathrm{s}}^1 ;$

• The two half-filled p-orbitals of O-atom must overlap with half-filled s-orbitals of H-atoms ; p-orbitals are mutually perpendicular to each other;
• Bond angle must be around ${90}^0$