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Q.

Bond angle in H2O is explained by            theory and bond angle in H2S , H2Se , H2Te  is explained by                 

 

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a

VBT , VBT

b

VBT , VSEPR

c

VSEPR , VBT

d

VSEPR , VSEPR

answer is C.

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Detailed Solution

In H2O molecule , Oxygen atom has four electron pairs around it 

According to VSEPR theory, shape must be tetrahedral

But due to lp-lp repulsions bond angle decreases to 104.5o

And  water molecule is bent (or) angular

In H2S , H2Se , H2Te , H2Po  the bond angle is around 90-93o

It is assumed that p-orbitals of central atom participate in bonding

\because P-orbitals are 90to each other , the bond angle is around  90o - 93o

Thus VBT explains the shapes of  H2S , H2Se , H2Te , H2Po

 

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