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Q.

Bond energy of N–N is x kJ mol–1.  Then bond energy of N ≡ N is 

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a

> 3x kJmol–1 

b

x kJmol–1

c

< 3x kJmol–1 

d

3x kJmol–1

answer is B.

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Detailed Solution

In N≡N , one sigma and two pi bonds are present.

sigma bond energy is higher than pi-bond energy.

Hence Then bond energy of N≡N is <3x  kjmol-1

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