Q.

Bond length in H2 molecule is 'x' nm. The covalent radius of deuterium is

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a

'x' nm

b

2x nm

c

4x nm

d

x/2 nm

answer is D.

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Detailed Solution

Given, B.L [i.n nm]= x
The isotopes of an element differed by their masses but they have same bond lengths i.e., The bond length in H2,D2T2 are same

IsotopeB.L
H2 ⇒ H-HXnm
D2 ⇒ D-DXnm
T2 ⇒ T-TXnm

Covalent radii [Cr]
 

Cr= Bond length 2

Cr=x2nm

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