Q.

Bond order in He2 species is

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a

0

b

1

c

2

d

3

answer is A.

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Detailed Solution

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He2(4e-)

Molecular orbital configuration is, σ1s2σ*1s2

Bond order=Nb-Na2=2-22=0

where, Nb= no. of bonding electrons , Na= no. of antibonding electrons.

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