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Q.

Bond order in He2 species is

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a

1

b

3

c

2

d

0

answer is A.

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Detailed Solution

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He2 ⇒ 4 electrons  [≤ 14e-]

MOE order

\large \sigma 1{s^2}\;{\sigma ^*}1{s^2}\
\large B.O = \frac{N_b - N_a}{2} = \frac{2 - 2}{2} = \frac{0}{2} = 0

Nb - No.of bonding electrons

Na - No of antibonding electrons  .

B.O is zero means no bond exist between the two helium atoms.

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