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Q.

Bond order of Carbon monoxide (CO) is(on the basis of molecular orbital theory)

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a

2

b

2.5

c

3

d

1.5

answer is C.

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Detailed Solution

$\begin{array}{l} C O : σ 1 s^{2} σ^{*} 1 s^{2} σ 2 s^{2} σ^{*} 2 s^{2} π 2 {P_{x}}^{2} = π 2 p_{y}^{2} σ 2 P_{y}^{2} \\ B o n d o r d e r = \frac{N o . o f b o n d i n g e l e c t r o n s (10) - N o . o f e l e c t r o n s i n A B M O (4)}{2} = 3 \end{array}$

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