Bond order of ${\mathrm{O}}_2^{+}$is same as in :

Explanation-

1. Electronic Configuration of O₂⁺: O₂ has 16 electrons. O₂⁺ loses one electron, leaving 15 electrons.

   Using the molecular orbital filling order:

   σ(2s)², σ*(2s)², σ(2p_z)², π(2p_x)² = π(2p_y)², π*(2p_x)² = π*(2p_y)¹

2. Bond Order Formula:

   Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2

   For O₂⁺, Bond Order = (10 - 5) / 2 = 2.5

Given Options

• N₂⁺: Bond order = (10 - 5) / 2 = 2.5
• CN^-: Bond order = (10 - 4) / 2 = 3.0
• CO: Bond order = (10 - 2) / 2 = 3.0
• NO⁺: Bond order = (10 - 5) / 2 = 2.5

Final Answer

The bond order of O₂⁺ is the same as in:

• N₂⁺
• NO⁺