Borate salts when heated with conc. $H_{2} {SO}_{4} and C_{2} H_{5} OH$ produce characteristic green colouration on flame due to the formation of volatile compound:

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$B_{2} O_{3}$

$B_{2} H_{6}$

${(C_{2} H_{5})}_{3} B$

${(C_{2} H_{5})}_{3} {BO}_{3}$

answer is C.

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Detailed Solution

$H_{3} {BO}_{3} + 3 C_{2} H_{5} OH ⟶ \underset{\begin{matrix} Methyl borate \\ (Green flame) \end{matrix}}{\underset{⏟}{{(C_{2} H_{5})}_{3} {BO}_{3}}} + 3 H_{2} O$

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