Borazine, also known as inorganic benzene, can be prepared by the reaction of 3-equivalents of "X" with 6-equivalents of "Y". "X" and "Y", respectively are

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$B_{2} H_{6} and {HN}_{3}$

${NH}_{3} and B_{2} O_{3}$

$B_{2} H_{6} and {NH}_{3}$

$B {(OH)}_{3} and {NH}_{3}$

answer is B.

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Detailed Solution

For the formation of Borazine, 3 equaivlents of B₃H₆ and 6 equivalents of NH₃ are required.
$3 B_{2} H_{6} + 6 {NH}_{3} \to 3 [{BH}_{2} {({NH}_{3})}_{2}]^{+} {[{BH}_{4}]}^{-} \overset{Heat}{\to} 2 B_{3} N_{3} H_{6} + 12 {NH}_{2}$

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