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a

${(BN)}_{n}$

b

$B_{2} H_{6}$

c

$B_{4} C$

d

${NH}_{3}$

answer is B.

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Detailed Solution

${nB}_{3} N_{3} H_{6} \overset{Δ}{\to} 3 {(BN)}_{n} + 3 {nH}_{2}$

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