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Q.

Boric acid $B {(O H)}_{3}$ is used as a mild antiseptic. What is the pH of a $0.0025 M$ aqueous solution of boric acid? The hydrogen ion arises principally from the following reaction $B {(O H)}_{3_{(a q)}} + H_{2} O_{(l)} ⇄ B {(O H)}_{4} {^{-}}_{_{(a q)}} + {H^{\oplus}}_{_{(a q)}}, K = 4.0 \times 10^{- 10}$

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answer is 6.

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Detailed Solution

$[H +] = \sqrt{K a \times C} = \sqrt{4 \times 10^{- 10} \times 0.0025} = 10^{- 6} M P^{H} = - \log (10^{- 6}) = 6$

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Boric acid B(OH)3 is used as a mild antiseptic. What is the pH of a 0.0025M aqueous solution of boric acid? The hydrogen ion arises principally from the following reaction B(OH)3(aq)+H2O(l)⇄B(OH)4 − (aq)+H⊕ (aq), K=4.0×10−10