Q.

Boron occurs in two varieties, namely  10B ( atomic mass: 10.01 amu) and  11B ( atomic mass: 11.01 amu ). The atomic mass of naturally occurring element is reported as 10.82 amu. The percent of  10B is 6this naturally occurring boron is 

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a

29

b

35

c

10

d

19

answer is B.

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Detailed Solution

If x is the fraction of  10B, we have x(10.01amu)+(1x)(11.01amu)=10.82amu

This gives x=0.19. Hence, percentage is 19%.

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