Both [Ni(CO)₄] and [Ni(CN)₄]^-2 are diamagnetic. The hybridization of nickel in these complexes, respectively are.

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dsp² and dsp²

dsp² and sp³

sp³ and sp³

sp³ and dsp²

answer is B.

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Detailed Solution

$\begin{array}{l} [Ni (CO)_{4}] - s p^{3}, dia ; {[Ni (CN)_{4}]}^{- 2} - - - \\ {dsp}^{2}, dia ; {[{NiCl}_{4}]}^{- 2} - - - {sp}^{3}, para \end{array}$

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