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Q.

Both [Ni(CO)₄] and [Ni(CN)₄]^2- are diamag-netic. The hybridizations of nickel in these respectively, are

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a

sp³, dsp²

b

sp³, sp³

c

dsp², dsp²

d

dsp², sp³

answer is B.

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Detailed Solution

In [Ni(CO)₄], Ni is in 0 oxidation state so there are 8 electrons in 3 d subshell and 2 electrons in 4s.
CO is the strong ligand, so it does pairing with the d subshell atom leaving one d subshell with unpaired electron.
now the electron from s shell shifts to d creating vacant space in s subshell and thus the hybridization is sp³
In [Ni(CN)₄]²⁻, Ni is in +2 oxidation state so it has 8 electrons in d subshell and CN is also a strong ligand which pairs with d subshell atom and leaves one d orbital empty and thus its hybridization is dsp²

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