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Q.

Both [Ni(CO)4] and [Ni(CN)4]2- are diamag-netic. The hybridizations of nickel in these respectively, are

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a

sp3, dsp2

b

sp3, sp3

c

dsp2, dsp2

d

dsp2, sp3

answer is B.

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Detailed Solution

  • In [Ni(CO)4​], Ni is in 0 oxidation state so there are 8 electrons in 3 d subshell and 2 electrons in 4s.
  •  CO is the strong ligand, so it does pairing with the d subshell atom leaving one d subshell with unpaired electron.
  • now the electron from s shell shifts to d creating vacant space in s subshell and thus the hybridization is sp3
  • In [Ni(CN)4​]2−, Ni is in +2 oxidation state so it has 8 electrons in d subshell and CN is also a strong ligand which pairs with d subshell atom and leaves one d orbital empty and thus its hybridization is dsp2
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Both [Ni(CO)4] and [Ni(CN)4]2- are diamag-netic. The hybridizations of nickel in these respectively, are