Bottle (A) contains 320 ml $H_{2} O_{2}$ solution and labelled with 11.2 Volume $H_{2} O_{2}$ and Bottle (B) contains 80 ml $H_{2} O_{2}$ having Molarity 3M, Contents of bottle (A) and bottle (B) are mixed and solution is filled in bottle (C). Select the correct label for bottle (C) in terms of Volume Strength and Strength (gram/litre)

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$5.6 V o l u m e a n d 41.286 g L^{- 1}$

$5.6 V o l u m e a n d 0.68 g L^{- 1}$

$15.68 V o l u m e a n d 47.6 g L^{- 1}$

$14.56 V o l u m e a n d 44.2 g L^{- 1}$

answer is B.

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Detailed Solution

$M_{1} = \frac{11.2}{11.2} = 1 M o l a r, M_{2} = 3 M o l a r$
$M_{m i x} = \frac{M_{1} V_{1} + M_{2} V_{2}}{(V_{1} + V_{2})} = \frac{1 \times 320 + 3 \times 80}{400} = 1.4 M o l a r$
$V o l u m e s t r e n g t h (x) = 11.2 M_{m i x} = 11.2 \times 1.4 = 15.68 V$
$S t r e n g t h (g r a m / l i t r e) = 1.4 \times 34 = 47.6 g r a m / l i t r e$