Bottle (A) contains 320 mL of $H_{2} O_{2}$ solution and labelled with 10 V $H_{2} O_{2}$ and bottle (B) contains 80 mL $H_{2} O_{2}$ having molarity 2.5 M. Content of bottle (A) and bottle {B) are mixed and solution is filled in bottle (C). Select the correct label for bottle (C) in terms of volume strength and g/litre. (Assume 1 mole of an ideal gas occupies 22.4 L at STP).

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13.6 V and 41.276 g/L

11.2 V and 0.68 g/L

5.6 V and 0.68 g/L

5.6 V and 41.286 g/L

answer is A.

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Detailed Solution

Here, we have,

$M = \frac{320 \times (\frac{10}{11.2}) + 80 \times 2.5}{400} = 1.214$

$V.S = 13.6$

in $g / L = 1.214 \times 34 = 41.276 g / L$ .

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